Please find the value of x and y.

x = 11

y = 3

Step-by-step explanation:

ΔTUV ≅ Δ HJK

JK = UV    {Corresponding parts of congruent triangles}

2x - 4 = 18

      2x = 18 + 4

      2x = 22

         x = 22/2

         x =  11

HK = TV

6y - 5 = 4y + 1           {Subtract 4y form both sides}

6y - 5 - 4y = 1

      2y - 5 = 1        {Add 5 to both sides}

           2y = 1 + 5

          2y = 6

            y = 6/2

            y = 3

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)