The proof that ΔACB ≅ ΔECD is shTriangles RQS and NTV have the following characteristics: • Right angles at ∠Q and ∠T
• RQ ≅ NT

Can it be concluded that ΔRQS ≅ ΔNTV by SAS? Why or why not?

Yes, one set of corresponding sides and one corresponding angle are congruent.
Yes, they are both right triangles.
No, it is necessary to know that another set of corresponding sides is congruent.
No, it is not possible for the triangles to be congruent. own.

Given: AE and DB bisect each other at C.
Prove: ΔACB ≅ ΔECD

Triangles A B C and C D E share common point C.

A flow chart has 5 boxes with arrows facing downward connecting the boxes. Each of the boxes are labeled. Box 1 contains line segment A E and line segment B E bisect each other at C and is labeled given. Box 2 contains line segment A C is-congruent-to line segment E C and is labeled definition of bisector. Box 3 contains question mark and is labeled vertical angles theorem. Box 4 contains line segment D C is-congruent-to line segment B C and is labeled definition of bisector. Box 5 contains triangle A C B is-congruent-to triangle E C D and is labeled SAS.

What is the missing statement in the proof?

∠BAC ≅ ∠DEC
∠ACD ≅ ∠ECB
∠ACB ≅ ∠ECD
∠BCA ≅ ∠DCA