the average time between accidents in a factory is 7 weeks. Find the probability that more than 8 weeks pass between accidents

0.2709

Step-by-step explanation:

Given that:

Average time between accidents (λ) = 7 weeks

Probability that more than 8weeks pass between accidents

P(x > 8) = 1 - P(x ≤8)

P(x > 8) = 1 - [p(0) + p(1) + p(2) + p(3) + p(4) + p(5) + p(6) + p(7) + p(8)]

To save computation time :

We can use a poisson distribution calculator :

Hence,

P(x > 8) = 1 - P(x ≤8)

P(x ≤8) = 0.72909

P(x > 8) = 1 - 0.72909

P(x > 8) = 0.2709

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3