What is the slope of a line perpendicular to the line whose equation is 6x+3y=-63

The slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

Step-by-step explanation:

We know that the slope intercept-form of the line equation is

where m is the slope and b is the y-intercept

Given the equation

simplifying the equation to write in the slope-intercept form

Thus, the slope = -2

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be:

Therefore, the slope of a line perpendicular to the line whose equation is 6x+3y=-63 will be: 1/2

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.