The perimeter of a triangle is 70 in. The shortest side is 11 in. less than the longest side. The middle side is 24 in. less than the combined lengths of the shortest and longest sides. Find the lengths of the three sides.

The sides are

6

inches,

8

inches and

10

inches

Explanation:

I'd suggest that the question should read 'The perimeter of a triangle is 24 inches. The longest side is 4 inches longer than the shortest side, and the shortest side is three-fourths the length of the middle side. How do you find the length of each side of the triangle?'

In this case the question can be answered. If

x

is the length of the middle side, then the shortest side is 3/4x and the longest side is 3/4x+4

x+3/4x+3/4x+4=24

10/4x=20

x=8

Then the shortest side is 6and the longest side is 10

Step-by-step explanation:

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.