A pilot flew a 400-mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed, the return trip took only 2 hours, with a tailwind. What was the speed of the wind?

40 miles per hour

Step-by-step explanation:

Given that:

Distance = 400 miles

Without tailwind :

Time taken = 2.5 hours

Speed = distance / time

Speed = 400 miles / 2. 5

Speed = 160 miles per hour

With tail wind :

Time taken = 2 hours

Net speed = 160 + x

X. = speed of tail wind

Distance = speed * time

400 = (160 + x) * 2

400 = 320 + 2x

400 - 320 = 2x

80 = 2x

x = 40

Speed of tailwind = 40 miles per hour.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)