A rocket is fired upward from the ground with an initial velocity of feet per second. Neglecting air resistance, the height of the rocket at any time t can be described in feet by the polynomial . Find the height of the rocket at .

Complete question is;

A projectile is fired upward from the ground with a velocity of 250 feet

per second. Neglecting air resistance, the height of the projectile in feet at

any time t, in seconds, can be described by the polynomial function P(t) = -16t² + 250t. Find the height at t = 4 seconds

744 ft

Step-by-step explanation:

We are told that the height of the rocket is represented by the polynomial P(t) = -16t² + 250t

Where t is time in seconds.

Now, we want to Find the height at t = 4 seconds

Thus;

P(4) = -16(4²) + 250(4)

P(4) = -256 + 1000

P(4) = 744 ft

hi there!

the answer will be d: 2