Graph the inequality on the axes below. 2x + y > -8
Y
10
9
8
6
5
-9
-S
- -
5
--
3 -2
3
+
2
3
+
5
9 10

The first step is to graph the line 2x + y = -8. To do this, we can graph the x and y-intercepts. Letting x = 0, we get y = -8, so the y-intercept is -8. Letting y = 0, we get 2x = -8, so x = -4.

Graph the line between the points (-4, 0) and (0, -8). The line should be dotted, because this is a strict inequality (the points on the line are not part of the solution).

The next step is to substitute a point - I like to use (0,0): when x and y are equal to zero, we have 2(0)+0>-8, which is true. Therefore, the right side of the graph (which contains the point (0,0)) should be shaded. Note: If the inequality was not true, you would want to shade the opposite side of the graph.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation:

answer: group b.

step-by-step explanation: