Find the coordinates of the intersection of the diagonals of parallelogram XYZW with vertices X(2, 2), Y(3, 6), Z(10, 6), and W(9,2). Hint: what do we know about
the diagonals of a parallelogram?

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hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^