Two sides of a parallelogram are 530 feet and 120 feet. The measure of the angle between these sides is 138°. Find the area of the parallelogram to the nearest square foot.

42,557 ft²

Step-by-step explanation:

Area of the parallelogram = 2×(Area of ∆)

Area of parallelogram = 2×(½×a×b×sin(θ))

Where,

a = 120 ft

b = 530 ft

θ = 138°

Plug in the values into the formula

Area of parallelogram = 2×(½×120×530×sin(138))

= 120×530×sin(138)

= 42,557 ft² (nearest square foot)

man its nopq i just guessed and got it right so uhh

g00d lucc

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.