Find the length of a rectangular lot with a perimeter of 126 meters if the length is 7 meters more than the width.

Let, the width = x

length = x+7

Now, 2(x+7+x) = 126

2(2x+7)=126

4x+14 = 126

4x = 112

x = 28

So, length would be(x+7) = 28+7 = 35meters

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

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