PLLSS HELP DUE IN 3 MINTUES!! Given the function h(x)=x^2+10x+21h(x)=x
2
+10x+21, determine the average rate of change of the function over the interval -10\le x \le -3−10≤x≤−3.

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x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1