Suppose a spring with spring constant 7 n/m is horizontal and has one end attached to a wall and the other end attached to a 3kg mass. suppose that the friction of the mass with the floor (i. e., the damping constant) is 3 n. s/m, and the forcing function is f(t) = 9sin (3t).

3x''+3x'+7x = 9sin 3t - to begin
then  Use the method of undetermined coefficients
Then  you need to find x′p and x′′p and sub them into equation, that will help you to solve A and B.

And finally you will have this :
3x′′+3x′+7x=9sin(3t)[−27Asin(3t)−27Bcos(3t)]+[9Acos(3t)−9Bsin(3t)]+[7Asin(3t)+7Bcos(3t)]=9sin(3t)(−20A+9B)sin(3t)+(−20B+9A)cos(3t)=9sin(3t)

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.