The polynomial-16t^2 + vt + h0 models the height, in feet, of a ball t seconds after it is thrown. In this polynomial, v represents the initial vertical velocity of the ball and h0 represents the initial height of the ball. Min throws a baseball from a height of 6 feet with an initial vertical velocity of 30 feet per second. Which polynomial models the height of the ball, in feet?

At the same time, Min’s little brother throws a baseball from a height of 4 feet with an initial vertical velocity of 20 feet per second. What polynomial models the height of this ball, in feet?

-16t^2 + ? t + ?

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

answer: the correct one is a

step-by-step explanation:

2nd one in the first row is correct

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?