a force of 12N acts for 5 s on a mass of 2 kg. What is the change in momentum of a mass of 10kg under the same condition

The change in momentum is: 60 N.s

Step-by-step explanation:

By Newton's second law:

F = ∆p / ∆t

Given that

Using the formula to determine the change in momentum

F = ∆p / ∆t

∆p = F × ∆t

     = 12 × 5

      = 60 N.s

Therefore, the change in momentum is: 60 N.s

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is: