Steel is an alloy of iron and carbon (98% iron, 2% carbon). Stainless steel is steel and chromium, (90% steel, 10% carbon). What amount of iron, carbon, and chromium are needed for 500 kg of stainless steel?

500 kg x 90% = 500x 0.9 = 450 kg of Steel is needed.

450 kg x 98% = 450 x 0.98 = 441 kg of iron needed.

450 x 0.02 = 9 kg of carbon is needed for the steel.

50 kg of chromium is needed.

Chromium is 10% carbon, 50x 0.1 = 5 kg of carbon is needed for the chromium.

Total iron = 441 kg

Total carbon = 9 + 5 = 14 kg

Total chromium = 50 kg

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.