5 years ago, Cheryl was d years old, Brandon is 2 years older than Cheryl. a. how old is Cheryl

b. how old is Brandon

c. what was the difference in their ages 5 years ago?

d. what is the sum of their ages now?

e. what will the sum of their ages be two years from now?

f. what will the difference of their ages be two years from now

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See explanation

Step-by-step explanation:

a. how old is Cheryl?

Cheryl's age = d + 5

b. how old is Brandon?

d + 5 + 2

= d + 7

c. what was the difference in their ages 5 years ago?

Cheryl age five years ago = d

Brandon's age five years ago = d + 2

Difference = d + 2 - d = 2 years

d. what is the sum of their ages now?

Cheryl's age = d + 5

Brandon age = d + 7

Sum = d + 5 + d + 7

= 2d + 12

e. what will the sum of their ages be two years from now?

Two years from now,

Cheryl's age = d + 5 + 2 = d + 7

Brandon age = d + 7 + 2 = d + 9

Sum = d + 7 + d + 9

= 2d + 16

f. what will the difference of their ages be two years from now

Two years from now,

Cheryl's age = d + 5 + 2 = d + 7

Brandon age = d + 7 + 2 = d + 9

Difference = Brandon age - Cheryl age

= (d + 9) - (d + 7)

= 2 years.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: