Part A )a painter leans a ladder up against a building. The base of the ladder is placed 7 feet from the building to reach a height of 24 feet. How long is the ladder Part B) The painter uses the same ladder from part A, but now needs to reach a height of 19 feet. How far away does the base of the ladder need to be placed from the building?

Part A). 25 feet

Part B). 16.25 feet

Step-by-step explanation:

Part A). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

            AC² = (24)² + 7²

            AC² = 576 + 49

            AC = √625

                  = 25 feet

Part B). By applying Pythagoras theorem in ΔABC,

            AC² = AB² + BC²

           (25)² = (19)² + x²

           625 = 361 + x²

           x² = 625 - 361

           x = √264

           x = 16.25 feet

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

- (2, -7)

- lines r and s and lines t and u must be parallel