Mr. Martin states that in order for the solution to the equation 3x + q = 6 to be positive, the value of q must be less than 6. Select a value of q that is less than 6 and show that the solution to the equation 3x + q = 6 is positive. Select a value of q that is not less than 6 and show that the solution to the equation 3x + q = 6 is not positive

Mr. Martin's statement is correct.

Step-by-step explanation:

First we select a value of q that is less than 6:

q = 3

Then we write the equation:

And solve for x:

The solution is positive because x > 0.

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Then we select a value of q that is not less than 6:

q = 9

Then we write the equation:

And solve for x:

The solution is negative because x > 0.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)