Two positive numbers have a sum of 54. if the larger number is 6 more than three time the smaller, find the two numbers

Let the numbers are = x.y

A.T.Q,

x+y=54

3x+6 = y

Substitute y value in above equation;

x+3x+6=54

4x=48

x=12

y=54-12=42

So, the numbers are 12 and 42

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the answer is 5/14.

hope this .