What is the point-slope form of a line that has a slope of 5 and passes through the point (3, –4)? y – 3 = 5[x – (–4)]
–4 – y1 = 5(3 – x1)
y – (–4) = 3(x – 5)
y – (–4) = 5(x – 3)

The answer is: y - (-4)= 5(x-3)

Point slope form is:

y-y1=m(x-x1)

m is your slope. They tell us the slope is 5. They also give you an ordered pair. Substitute this ordered pair into the point slope equation for the x1 and y1 values.

brainlest plz

Step-by-step explanation:

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

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step-by-step explanation: