awnser one is 7 and question 2 is -10
Step-by-step explanation:
β12β2ββ55=? Β question one
In the first fraction, the negative numerator and negative denominator cancel each other.
Since the the second fraction is negative and you are subtracting, remove the negative sign and switch the operation to addition.
The equivalent equation is
122+55=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(12/2, 5/5) = 10
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(122Γ55)+(55Γ22)=?
Complete the multiplication and the equation becomes
6010+1010=?
The two fractions now have like denominators so you can subtract the numerators.
Then:
60+1010=7010
Since 70 divided by 10 equals 7 then,
7010=7
Therefore:
β12β2ββ55=7 Β Β
Question 2
β81+6β3=?
In the second fraction, move the negative sign from the denominator to the numerator and the value remains the same.
The equivalent equation is
β81+β63=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(-8/1, -6/3) = 3
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(β81Γ33)+(β63Γ11)=?
Complete the multiplication and the equation becomes
β243+β63=?
The two fractions now have like denominators so you can add the numerators.
Then:
β24+β63=β303
Since -30 divided by 3 equals -10 then,
β303=β10
Therefore:
β81+6β3=β10
Solution by Formulas
Apply the fractions formula for addition, to
β81+6β3
and solve
(β8Γβ3)+(6Γ1)1Γβ3
=24+6β3
=30β3
=β10