Write an equation of the line that passes through (0, 3) and (−5, 2.5).

The equation of the line will be in the form:

y=mx+c

where m is the slope (gradient) and c is the y-intercept.

To find the slope, we use:

m=y2−y1x2−x1

It doesn't matter which point we decide is (x1,y1) and which we choose as (x2,y2, since the formula will work either way.

m=0−(−5)3−(−3)=56

Now we can use the slope and the coordinates of one point - either will do - to find the y-intercept:

y=mx+c

0=56(3)+c=156+c

Rearranging:

c=0−156=−156

Over all, then, the equation of the line is:

y=56x−156

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: