An equilateral triangle with the lengths of its sides given in terms of a and b.
(4a)cm
(3b)cm
(a + b + c)cm
Find a and b and hence find the length of the
sides of the triangle.

Step-by-step explanation:

4a = 3b

4a = a+b+c

c = 3a-b, so

4(3a-b) = 3b

12a-4b = 3b

12a = 7b

subtracting,

8a = 4b

or

4a = 2b

But, 4a = 3b, so

2b = 3b

b=0

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.