The area of a rectangle is 32 square inches. The length is 4 inches more than its width. Write and solve an equation to find the length and width of the rectangle. Show your work.

Width = 4 in

Length = 8 in

Step-by-step explanation:

Given:

Area of a rectangle = 32 in²

Find:

Length and width

Computation:

Assume;

Width = x

Length = x + 4

Area of a rectangle = lb

32 = (x+4)(x)

x² + 4x = 32

x² + 4x - 32 = 0

x² + 8x - 4x - 32 = 0

x(x+8) - 4(x+8) = 0

(x-4)(x+8)

x = 4 , x = -8

So,

Width = x = 4 in

Length = x + 4 = 4 + 4 = 8 in

homozygous. one is homozygous, while two is heterozygous.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~