How many roots do the functions have in common?

f(x)=2x^2-4x-16

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Step-by-step explanation:

Given the function f(x)=2x^2-4x-16

To know the amount of roots that the function have in common, we need to first factorize the expression as shown;

f(x)=2x^2-4x-16

f(x)=2x^2-8x-16

Let f(x) = 0

0 =2x^2-4x-16

2x^2-4x-16 = 0

Divide through by 2;

x^2-2x-8 = 0

x^2 - 4x + 2x - 8 = 0

x(x-4)+2(x-4) = 0

(x+2)(x-4) = 0

x = -2 and 4

Hence the roots of the function are -2 and 4. They did not have any common roots

you already gave the answer

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a