Can anyone teach pls. Given that PR= 17cm and SR= 6cm. Find the length, in cm of TS.

9cm

Step-by-step explanation:

Since PQST is a rectangle, ∠QST=∠QSR=∠90º. So triangle QSR is a right triangle.By the Pythagorean Theorem and that SR=6 and QR=10, we can say that 6^2+b^2=10^2. So, 36+b^2=100. And b^2=64 and b=8. So QS=8.Now we know that QS=PT=8.By the Pythagorean Theorem and that PR=17 and PT=8, we can say a^2+8^2=17^2. So, a^2+64=289. And a^2=225 and a=15.We know that TR=15 and SR=6 and TR-SR=TS, so 15-6=9.