How do I solve this and check all the solutions?

Given Eq:

Solving this:

Squaring both sides,

➝ x + 3 = (x - 3)²

➝ x + 3 = x² - 6x + 9

Now shifting RHS to LHS,

➝ x + 3 - x² + 6x - 9 = 0

➝ -x² + 7x - 6 = 0

➝ x² - 7x + 6 = 0

Now finding the values of x by middle term factorisation,

➝ x² - 6x - x + 6 = 0

➝ x(x - 6) - 1(x - 6) = 0

➝ (x - 1)(x - 6) = 0

➝ x = 1 or 6.

But here, you can see, x = 1 is not a solution to the original equation because when we say about square roots, value can't be negative.

Hence,

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ok

step-by-step explanation: