Hello I need help with this, Don Manuel has 600m of fence to build a rectangular-shaped corral. You will take advantage of a very long wall as one of the sides of the pen, that is, on the side of the wall you will not use fence. What should be the dimensions of the pen with maximum area among all those that use 600m of fence?

 If the wall is 300 meters long, the dimensions of the fence with the maximum area will be 300 × 150 = 45000 m²

Step-by-step explanation:

try combinations in a chart

190 × (600-190)/2 = 38950  = 190 × 205       increasing area

200 × (600-200)/2 = 40000   = 200 × 200

220 × (600-220)/2 = 41800   == 220 × 190

240 × (600-240)/2 = 43200   == 240 × 180

260 × (600-260)/2 = 44200  == 260 × 170

280 × (600-280)/2 = 44800 .  == 280 × 160

300 × (600-300)/2 = 45000  == 300 × 150  Maximum Area

310 × (600-310)/2 = 44950 . == 310 × 145    decreasing area

320 × (600-320)/2 = 44800 . == 320 × 140    

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: