You roll a standard dice two times. What is the probability of getting a 6 on the first roll, then an even number on the second roll?

4 out of 12 chance.

Step-by-step explanation:

So its a 1 out of 6 chance for the first die, and a 3 out of 6 chance on the second die, so a 4 out of 12 chance of what was said to happen.

First die:

You want to roll a 6. There is one number on each side of the die, and there are 6 sides. Since you can only get a side with 6 once, you have a 1 out of 6 chance of landing a 6.

Second die:

You want to roll an even number. There are 3 even numbers on the die (2, 4, and 6), and there are 6 sides, with the other 3 sides being odd (1, 3, and 5). Since you can only get a side that is even three times, you have a 3 out of 6 chance of landing an even number (2, 4, or 6).

Combine these probabilities together, and you result in a 4 out of 12 chance of getting the requirements. The 4 comes from adding the chance of getting a 1 and 3 even numbers, and the 12 comes from adding the 2 6's (since two dices would result in 12 sides).

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step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times

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step-by-step explanation:

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