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Mathematics, 28.11.2020 07:20 yasarhan2

Here is an equation, and then all the steps Clare wrote to solve it: 14 x βˆ’ 2 x + 3 = 3 ( 5 x + 9 )
12 x + 3 = 3 ( 5 x + 9 )
3 ( 4 x + 1 ) = 3 ( 5 x + 9 )
4x+1=5x+94 x + 1 = 5 x + 9
1=x+91 = x + 9
-8=x

Here is the same equation, and the steps Lin wrote to solve it:
βˆ’ 8 = x
14x-2x+3=3\left(5x+9\right)14 x βˆ’ 2 x + 3 = 3 ( 5 x + 9 )
12x+3=3\left(5x+9\right)12 x + 3 = 3 ( 5 x + 9 )
12x+3=15x+2712 x + 3 = 15 x + 27
12x=15x+2412 x = 15 x + 24
-3x=24βˆ’ 3 x = 24
x=-8

Are both of their solutions correct? Explain your reasoning.

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Answers: 3

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Here is an equation, and then all the steps Clare wrote to solve it: 14 x βˆ’ 2 x + 3 = 3 ( 5 x + 9 )...
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