How do i find the value of x

answer x=150°

here PQRS is a cyclic quadrilateral

so, W.K.T

the sum of opp.angles of cyclic quadrilateral is 180°

now, PQR+PRS=180°

Here,PSO+OSR=PRS

PQR+PSO+OSR=180°

120°+45°+OSR=180°

165°+OSR=180°

OSR=180°-165°

OSR=15°

now, OS=OR [ Radii of circle]

so, OSR=ORS [ Angle opp.equal side ]

consider triangle OSR,

OSR+SOR+ORS=180° [ angle sum property of triangle ]

15°+15°+SOR=180°

x=180°-30°

x=150°

hope it will help you

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