A grocery store recently changed their apple supplying vendor. The vendor told the store manager that the mean weight for each apple is bell-shaped with # mean of 7.5 ounces and a standard deviation of 1.33 ounce (a) One customer comes to this grocery store and randomly picks 25 apples. What is the mean and standard deviation of the distribution of the mean weight for 25 apples? (b) What is the probability that the mean weight of 25 apples exceeds 8.2 ounces? (c) Another customer randomly picks 10 apples. Will the probability of the mean weight that the 10 apples exceeds 8.2 ounces of this customer be higher than the last customer in part b? Explain it.

b) 0.0042495

c) 0.048021

Hence, the probability of the mean weight that the 10 apples exceeds 8.2 ounces of this customer wil be higher than the last customer in part b because the number of random samples in part b is greater that that in part c

Step-by-step explanation:

mean of 7.5 ounces and a standard deviation of 1.33 ounce

When random number of samples are given, we solve using z score with the formula

= z = (x-μ)/σ/√n, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

n is the random number of samples

(a) One customer comes to this grocery store and randomly picks 25 apples. What is the mean and standard deviation of the distribution of the mean weight for 25 apples?

(b) What is the probability that the mean weight of 25 apples exceeds 8.2 ounces?

x > 8.2 ounces

= z = (x - μ)/σ/√n

z = (8.2 - 7.5)/1.33/√25

z = (8.2 - 7.5)/1.33/5

z = 2.63158

Probability value from Z-Table:

P(x<8.2) = 0.99575

P(x>8.2) = 1 - P(x<8.2) = 0.0042495

(c) Another customer randomly picks 10 apples. Will the probability of the mean weight that the 10 apples exceeds 8.2 ounces of this customer be higher than the last customer in part b?

For n= 10

x > 8.2 ounces

= z = (x - μ)/σ/√n

z = (8.2 - 7.5)/1.33/√10

z = 1.66436

Probability value from Z-Table:

P(x<8.2) = 0.95198

P(x>8.2) = 1 - P(x<8.2) = 0.048021

Hence, the probability of the mean weight that the 10 apples exceeds 8.2 ounces of this customer wil be higher than the last customer in part b because the number of random samples in part b is greater that that in part c

this is the formula: v = the value of investment at the end of the time period

p = the principal amount (the initial amount invested)

r = the annual interest rate

n = the annual frequency of compounding (how many times a year interest is added)

t = the number of years the money is invested

^ means raise to the power of

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92