Three times the sum of three consecutive integers is 72. What are the integers? a. 4, 5, 6 c. 9, 10, 11 b. 7, 8, 9 d. 6, 7, 8

The three integers whose three times the sum of three consecutive integers is 72 will be: 7, 8, 9

Step-by-step explanation:

Let x, y, and z be the three consecutive integers

The sum of x, y, and z will be: x+y+z

The three times the sum of three consecutive integers is 72.

so the equation becomes:

3(x+y+z)=72

Now, putting x = 7, y=8 and z=9 in the L.H.S equation to check

3(x+y+z)

⇒ 3(7+8+9)

⇒ 3(24)

⇒ 72

Therefore, it is clear that the three integers whose three times the sum of three consecutive integers is 72 will be: 7, 8, 9

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