Let F = (2, 3). Find coordinates for three points that are equidistant from F and the y-axis. Write an equation that says P = (x, y) is equidistant from F and the y-axis

The equation that says P is equidistant from F and the y-axis is .

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

Step-by-step explanation:

Let and , where is a point that is equidistant from F and the y-axis. The following vectorial expression must be satisfied to get the location of that point:

(1)

If we know that and , then the resulting vectorial equation is:

The equation that says P is equidistant from F and the y-axis is .

If we know that , and , then the coordinates for three points that are equidistant from F and the y-axis:

(1, 0), (1, 3/2) and (1,6) are three points that are equdistant from F and the y-axis.

answer:   y=2x-3

step-by-step explanation:

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8