The sum of two numbers is 116 and their difference is 18. Find the larger number.

67

Step-by-step explanation:

let larger number be x and the other be y.

x - y = 18

x = 18+y

now, x + y = 116

therefore, 18+y+y= 116

18 + 2y =116

2y = 116-18

2y = 98

y = 98/2 = 49

larger number = 49 + 18 = 67

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

well your weight will go up if you are not going to burn the calories/ carbs

step-by-step explanation: