-6x + 5xy - 9y - 3x + 7 =need help again!!sorry

=5xy−9x−9y+7

Step-by-step explanation:

Let's simplify step-by-step.

−6x+5xy−9y−3x+7

=−6x+5xy+−9y+−3x+7

Combine Like Terms:

=−6x+5xy+−9y+−3x+7

=(5xy)+(−6x+−3x)+(−9y)+(7)

=5xy+−9x+−9y+7

=5xy−9x−9y+7

2

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.