The half-life of radioactive radium (226Ra) is 1599 years. What percent of a present amount of radioactive radium will remain after 275 years?

88.76%

Step-by-step explanation:

Given that :

Half life of radium = 1599 years

Percentage that will remain after 275 years

Using the relation :

y = Ae^kt

Where ; A = mass of radium and t = half life = 1599, A = initial mass

By 1599, the mass of radium will be half its initial

Hence,

y = initial / 2 = A /2

A/2 = Ae^kt

To obtain the value of k

0.5 = e^1599k

In0.5 = 1599k

k = (In0.5)/1599

k = - 0.0004335

Hence,

y = Ae^-0.0004335t

Amount of radium. After 275 years : t = 275

y = Ae^-0.0004335*275

y = A0.8876191

y = 0.8876191 of intial amount

Hence, 0.8876191 * 100%

= 88.76%

answer: 7270

step-by-step explanation:

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.