Hello, please, I need the answers!! Each year a school booster club holds a dance to raise funds. In the past, the profit of the club makes after paying for the bank and other costs has been modeled by the function p(t) = -16t^2 - 800t - 4000 where t represents the ticket price in dollars. a. What ticket price gives the maximum profit? b. What is the maximum profit? c. What ticket prices would generate a profit of $5000?

Step-by-step explanation:

Given the profit a club makes after paying for the bank and other costs modeled by the function

p(t) = -16t^2 - 800t - 4000

t is the ticket price

The maximum profit occurs when dp/dx = 0.

dp/dx = -32t-800

since dp/dx

0 = -32t-800

32t = -800

t = -800/32

t = - 25

Hence ticket price gives the maximum profit is $-25

b) to get the maximum profit, substitute t = -25 into the modelled function

p(t) = -16t^2 - 800t - 4000

p(-25) = -16(-25)² - 800(-25)- 4000

p(-25) = -10000+20000-4000

p(-25) = 6000

Hence maximum profit is $6000

c) To get the ticket prices would generate a profit of $5000, we will substitute p(t) = 5000 and find t

p(t) = -16t^2 - 800t - 4000

5000 = -16t^2 - 800t - 4000

-16t^2 - 800t - 4000 -5000 = 0

16t^2 + 800t + 9000 = 0

Step-by-step explanation:

Given the profit a club makes after paying for the bank and other costs modeled by the function

p(t) = -16t^2 - 800t - 4000

t is the ticket price

The maximum profit occurs when dp/dx = 0.

dp/dx = -32t-800

since dp/dx

0 = -32t-800

32t = -800

t = -800/32

t = - 25

Hence ticket price gives the maximum profit is $-25

b) to get the maximum profit, substitute t = -25 into the modelled function

p(t) = -16t^2 - 800t - 4000

p(-25) = -16(-25)² - 800(-25)- 4000

p(-25) = -10000+20000-4000

p(-25) = 6000

Hence maximum profit is $6000

c) To get the ticket prices would generate a profit of $5000, we will substitute p(t) = 5000 and find t

p(t) = -16t^2 - 800t - 4000

5000 = -16t^2 - 800t - 4000

-16t^2 - 800t - 4000 -5000 = 0

t^2 + 50t + 562.5= 0

Factorize

-50±√2500-4(562.5)/2

t = -50±√2500-2250)/2

t = -50±15.81/2

t = -65.81/2 and -34.19/2

t = -32.91 and -17.09

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.