Marine fuel is a combination of gasoline and motor oil. The standard gasoline and oil mixture is about 98% gasoline and about 2% motor oil. The "break in" mixture for a new engine is about 96% gasoline and about 4% motor oil. a. Write an equation in standard form that models the possible combinations of each kind of mixture you can prepare using 6 gallons of gasoline. b. If you prepare 4 gallons of the "break in" mixture, how much gasoline will you have for the standard mixture?

With 6 gallons of gasoline you could obtain 6.12 gallons of standard mixture or 6.25 gallons of break in mixture. In turn, if 4 gallons of break in mixture were prepared, there would be 2.16 gallons of gasoline left to prepare standard mixture.

Since the standard gasoline and oil mixture is about 98% gasoline and about 2% motor oil, and the "break in" mixture for a new engine is about 96% gasoline and about 4% motor oil, to determine the possible combinations of each kind of mixture you can prepare using 6 gallons of gasoline and, if you prepare 4 gallons of the "break in" mixture, how much gasoline will you have for the standard mixture, the following calculations should be performed:

A)

Therefore, with 6 gallons of gasoline you could obtain 6.12 gallons of standard mixture or 6.25 gallons of break in mixture.

B)

Therefore, if 4 gallons of break in mixture were prepared, there would be 2.16 gallons of gasoline left to prepare standard mixture.

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0.98g+ 0.02m= 7.1224 gallons standard mixture

0.96g+ 0.04m= 6.25 gallons break oil

3.92 gallons of gasoline  is required for  4 gallons the standard mixture

Step-by-step explanation:

If we have to use 6 gallons of gasoline this means that 98%= 6 gallons and 2% would be 6/98*2

Gasoline: Motor oil

6              :    x

98        : 2

Using the product rule

x= 6*2/98= 0.1224 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the standard oil the equation would be

0.98g+ 0.02m= 7.1224 gallons standard mixture

For break in oil

Gasoline: Motor oil

6              :    x

96        : 4

Using the product rule

x= 6*4/96= 0.25 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the break oil the equation would be

0.96g+ 0.04m= 6.25 gallons break oil

Part b. For  4 gallons of the "break in" mixture

96% of the 4 gallons of the "break in" mixture is gasoline =  3.84 gallons of gasoline

4% of 4 = 0.16 gallons of motor oil

Now the standard mixture 4 gallons would contain 98 % of gasoline and 2 % of motor oil

98% of 4 gallons= 3.92 gallons of gasoline

2% of  4 gallons= 0.08 gallons of motor oil.

any of them that add up to 180 degrees.