If f(x) = 3x - 1 and 2f(b) = 28, what is the value of f(2b)?

=29

Step-by-step explanation:

2f(b)=28

divide by 2

f(b)=14

f(b)=3b-1

3b-1=14

add 1 on both sides

3b=15

divide by 3

b=5

f(5)=14

let's plug that in

f(2×5)=3(2×5)-1

f(10)=30-1

f(10)=29

what level of math? also i don't need to be paid if i can you.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: