Let E be the event that a corn crop has an infestation of ear worms, and let B be the event that a corn crop has an infestation of corn borers. Suppose that P(E) = 0.24, P(B) = 0.16, and P(E and B) = 0.13. Find the probability that a corn crop has either an ear worm infestation, a corn borer infestation, or both. a. 0.53
b. 0.13
c. 0.6
d. 0.27

d. 0.27

Step-by-step explanation:

Calculation to determine the probability that a corn crop has either an ear worm infestation, a corn borer infestation or both

Using this formula

P(E U B) = P(E) +P(B) -P(E n B)

Let plug in the formula

P(E U B) =0.24 + 0.16 -0.13

P(E U B)=0.27

Therefore the probability that a corn crop has either an ear worm infestation, a corn borer infestation or both will be 0.27

a = 11 : 4

b = 38

c = 1 for every 6

98%

step-by-step explanation: