Find three consecutive odd numbers such that the sum of three less than three times the smallest plus twice the largest is 140?

First no. = 27

Second no. = 29

Third no. = 31

Step-by-step explanation:

First no. = a (smallest no.)

Second no. = a + 2

Third no. = a + 4 ( largest no.)

Given,

3a - 3 + 2(a + 4) = 140

3a - 3 + 2a + 8 = 140

(3a + 2a) + (-3 + 8) = 140

5a + 5 = 140

5a = 140 - 5

5a = 135

a = 135/5

a = 27

First no. = a = 27

Second no. = a + 2 = 29

Third no. = a + 4 = 31

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.