What are the zeros of the polynomial function f(x) = x3 + 10x2 + 24x?

f(x) = x³- 10x² + 24x

f(x) = x ( x² + 10x + 24)

f(x) = x (x + 6)(x+4)

x=0

x+6 = 0

x = 0-6

x= -6

x+4 = 0

x = 0-4

x= -4

zero's would be: 0, -6 and -4,

So it is your third choice down.

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

pls mark as brainliest