and \overline{BA} \cong \overline{DC}.
Mathematics, 24.11.2020 17:00 sydneip2394
Given: \overline{BD} \cong \overline{AC}
BD ≅ AC
and \overline{BA} \cong \overline{DC}.
BA ≅ DC
Prove: \triangle BAD \cong \triangle CDA△BAD≅△CDA.
Answers: 1
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Given: \overline{BD} \cong \overline{AC}
BD ≅ AC
and \overline{BA} \cong \overline{DC}.
and \overline{BA} \cong \overline{DC}.
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