If two lines on a graph meet at one coordinate, does that mean the two equations had one solution, no solution or infinitely many solutions?

One solution

Step-by-step explanation:

It is simple to remember the one, no, and infinitely many solutions and how they work by thinking about how many place the lines touch or cross. you'll get the hang of it =) keep it up.

They both had one solution

Step-by-step explanation:

If the graphs of the equations intersect, then there is one solution that is true for both equations. When the lines are parallel, there are no solutions, and sometimes the two equations will graph as the same line, in which case you have an infinite number of solutions.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.