water flows into a reservoir at a rate of 1500+7t^2 gallons/hour. Since there is a tiny hole in the reservoir, the water leaks out at a rate of 4t+t^2 gallons/hour. What is the net change in the amount of water in the reservoir over the time interval of [1,5]

9514 1404 393

  6200 gallons

Step-by-step explanation:

The rate of change of volume is the difference between the inflow rate and the outflow rate.

  v'(t) = (1500 +7t^2) -(4t +t^2) = 6t^2 -4t +1500

The change in volume over the time interval of interest is the integral of this expression over that interval:

The amount of water in the reservoir increases by 6200 gallons over the time interval.

answer: 25 is the correct answer

step-by-step explanation:

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .