What is the equation of the line that is perpendicular to the line y = 1/3x + 7 and passes through the point (1, 5)?

y = -3x + 8

Step-by-step explanation:

The slope of a perpendicular line to the original equation is the opposite reciprocal of the slope of the original equation. This makes the opposite reciprocal -3, so the slope of the perpendicular line is -3.

Now that we have found the slope, we will put it into the formula for slope, y = mx + b. This results in getting y = -3x + b.

We know the values for x and y, (1,5) respectively. Plug these values into y = -3x + b.

5 = -3(1) + b

b = 8

This means that 8 is your y intercept and goes into place for b

Therefore, your resulting equation is y = -3x + 8

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answer: 1 and 3

step-by-step explanation: