PLEASE HELPP In Triangle XYZ, A is the midpoint of XY, B is the midpoint of YZ, and C is the midpoint of XZ.
Also, AY = 7. BZ = 8, and XZ = 18. What is the perimeter of Triangle ABC?
Make sure you explain why and show all your work.

The perimeter of triangle ABC is 33.

Explanation:

AY = 7 is half of the line of XY so we would then multiply 7 by 2:

7 x 2 = 14

and we would then do this to all of our numbers:

8 x 2 = 16

18 x 2 = 36

now we make a full equation for the answer of the perimeter of triangle XYZ:

14 + 16 + 36 = 66

66 is the perimeter of triangle XYZ.

We would then divide this answer by 2 to find the perimeter of ABC because it is half of XYZ:

66 ÷ 2 = 33

The perimeter of triangle ABC is 33

Hope this helps! :)

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.