Solve |y + 2| > 6
pls help

Step-by-step explanation:

Definition of an absolute value is:

1). Assume that (y + 2) ≥ 0, then

y + 2 > 6 ⇒ y > 4

2). Now, if (y + 2) < 0, then

- (y + 2) > 6 ⇔ - y - 2 > 6 ⇒ y < - 8

y ∈ ( - ∞ , - 8) ∪ (4 , ∞ )

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743